CSIR UGC NET Admit Card 2025

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CSIR UGC NET December 2024 Exam Schedule and Admit Card Released

Published: February 26, 2025

The National Testing Agency (NTA) is conducting the CSIR UGC NET / JRF Exam for December 2024. The examination schedule has been released, and admit cards are now available for download. The exam will be held in two shifts.

NTA CSIR UGC NET December 2024: Details

Here’s a summary of the key dates and details for the NTA CSIR UGC NET December 2024 exam.

Important Dates:

  • Notification Date: December 9, 2024
  • Application Start Date: December 30, 2024
  • Last Date to Apply: January 2, 2025
  • Fee Payment Last Date: January 3, 2025
  • Correction Window: January 4 – 5, 2025
  • Exam Date: February 28, 2025 to March 2, 2025
  • Exam City Display: February 20, 2025
  • Admit Card Release: February 25, 2025

Application Fee:

  • General/EWS: Rs. 1150/-
  • OBC: Rs. 600/-
  • SC/ST: Rs. 325/-

Payment of the examination fee must be made through Debit Card / Credit Card / Net Banking / UPI or other online payment methods.

Age Limit:

Age relaxation is applicable as per NTA CSIR UGC NET rules. You can use an Age Calculator to determine your eligibility. Check out more resources at PSC Notes.

Exam Details:

  • Exam Name: NTA CSIR UGC NET Examination December 2024

Educational Qualification:

Candidates must possess the following qualifications to be eligible for the NTA CSIR UGC NET Exam December 2024:

  • M.Sc / Equivalent Degree with 55% Marks (For General / OBC) & 50% Marks (For SC / ST and PH)
  • Candidates with Integrated Courses, B.E / B.Tech / B.Pharma, and MBBS degrees are also eligible.

CSIR UGC NET 2024: Subjects Offered

  • Chemical Science
  • Earth, Atmospheric, Ocean and Planetary Science
  • Life Science
  • Mathematical Science
  • Physical Science

Mode of Selection:

Selection will be based on an Online Examination.

How to Download the NTA CSIR UGC NET Admit Card 2025

Candidates can download their admit cards by following these steps:

  1. Visit the official NTA website.
  2. Locate the link for downloading the NTA CSIR UGC NET Admit Card.
  3. Click on the provided link.
  4. You will be redirected to the login page.
  5. Enter the following details:
    • Registration Number
    • Password/Date of Birth (DOB)
  6. Click the ‘Login’ button.

Candidates can also download their NTA CSIR UGC NET Admit Card from the official NTA website. For more information, visit PSC Notes.

Important Links:

  • Download Admit Card: (Please replace with the actual link if available)
  • Check Exam City Details: (Please replace with the actual link if available)
  • Download Exam Schedule: (Please replace with the actual link if available)
  • Apply Online: (Please replace with the actual link if available)
  • Download Date Extend Notice: (Please replace with the actual link if available)
  • Download Notification: (Please replace with the actual link if available)
  • Official Website: https://ugcnet.nta.nic.in/

FAQs:

  • Q: When did the online application link start for NTA CSIR UGC NET December 2024?
    • A: Online applications started on December 9, 2024.
  • Q: What is the last date to apply online for NTA CSIR UGC NET December 2024?
    • A: The last date to apply online was January 2, 2025.
  • Q: What is the age limit for NTA CSIR UGC NET December 2024?
    • A: The age limit varies based on the category (JRF or Lectureship/Assistant Professor). Refer to the official notification for detailed information. Use the Age Calculator to determine your eligibility.
  • Q: What is the qualification required for NTA CSIR UGC NET December 2024?
    • A: Candidates must possess a Post Graduation degree. Refer to the official notification for complete details.
  • Q: How to apply for NTA CSIR UGC NET December 2024?
    • A: Apply online through the official website.
  • Q: How to download the result of NTA CSIR UGC NET December 2024?
    • A: The result can be downloaded by entering your registration number/roll number and DOB (Date of Birth). The official download link will be made available.

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